Hi I cant seem to find the roots of this x^2 - 5x + 12
I cant do it the -b formula or standard factors?
The discriminant is negative an so you will get two complex solutions. To find these use the quadratic formula
$\displaystyle x = \frac{5 \pm \sqrt{5^2-4\cdot 1 \cdot 12}}{2} = \frac{5 \pm i \, \sqrt{23}}{2}$
$\displaystyle x = \frac{5}{2} + i\, \frac{\sqrt{23}}{2} \: \text{or} \: \frac{5}{2} - i\, \frac{\sqrt{23}}{2}$