log3x + log3(x + 2) = 1 how do i prove this? So far, i have: = log3[x(x+2)] = log3[x^2 + 2x] and i can't get any farther?
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Originally Posted by snypeshow log3x + log3(x + 2) = 1 how do i prove this? So far, i have: = log3[x(x+2)] = log3[x^2 + 2x] and i can't get any farther? Change is from a log to a non log form; therefore, it will now look like this: Can you solve it now? In addition, don't forget to check your answers
so I would get x = sqrt(3 - 2x) ?
Yes, because to get rid of the power u need to square root the rest
YES! thanks alot guys!!!! man, there's nothing you guys cant answer :P
Last edited by snypeshow; Nov 22nd 2009 at 03:41 PM.
Originally Posted by snypeshow so I would get x = sqrt(3 - 2x) ? I do not agree with your answer ... move the subtract 3 from both sides factor solve for x: x=-3, x=1 check to make sure you do not get a negative log .... since -3 does give you a negative log your solution set is 1
Originally Posted by RRH I do not agree with your answer ... move the subtract 3 from both sides factor solve for x: x=-3, x=1 check to make sure you do not get a negative log .... since -3 does give you a negative log your solution set is 1 Yeh you are right! Hmpff made a silly mistake there. No point in calculating X at one side if there's still a X at the other side
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