log3x + log3(x + 2) = 1
how do i prove this?
So far, i have:
= log3[x(x+2)]
= log3[x^2 + 2x]
and i can't get any farther?
I do not agree with your answer ...
$\displaystyle
x^2+2x=3^1
$
move the subtract 3 from both sides
$\displaystyle
x^2+2x-3=0
$
factor
$\displaystyle
(x+3)(x-1)=0
$
solve for x:
x=-3, x=1
check to make sure you do not get a negative log .... since -3 does give you a negative log
your solution set is 1