yea i did that already and ive gotten so many diffrent answers. and even plugged ihem back in to see if they r right... but no luck... but here is my last work. i found z and y which was z-25/91 and y=160/819 is that right?
basically i tried to ways. one was making 1x+2y-2z=3 into everything equal to 1. and another i did was i just did a regular system of quation.. but yeah. help please.!
(1): x + 2y - 2z = 3
(2): $\displaystyle 2x - \frac{1}{3}y + \frac{1}{3}z = \frac{61}{21}$
(3): $\displaystyle \frac{3}{2}x - \frac{3}{2}y - z = \frac{43}{14}$
(1) x 42 $\displaystyle \rightarrow$ 42x + 84y - 84z = 126
(2) x 21 $\displaystyle \rightarrow$ 42x - 7y + 7z = 61
(3) x 28 $\displaystyle \rightarrow$ 42x - 42y - 28z = 86
(2) - (3) $\displaystyle \rightarrow$ 35y + 35z = -25
7y + yz = -5
7z = -5 - 7y ...(4)
From (1) $\displaystyle \rightarrow$ 42x = 126 - 84y + 84z
(4) into (1) $\displaystyle \rightarrow$ 42x = 126 - 84y + 12(-5 - 7y)
42x = 126 - 60 - 84y - 84y
42x = 66 - 168y ...(5)
(4) and (5) into (2) $\displaystyle \rightarrow$ (66 - 168y) - 7y + (-5 - 7y) = 61
182y = 0
y = 0 ...(6)
(6) into (4) $\displaystyle \rightarrow$ 7z = -5 - 0
$\displaystyle z = -\frac{5}{7}$ ...(7)
(6) and (7) into (1) $\displaystyle \rightarrow$ $\displaystyle x + 0 - 2(-\frac{5}{7}) = 3$
x = $\displaystyle 3 - \frac{10}{7}$
x = $\displaystyle \frac{11}{7}$