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Math Help - Matrices

  1. #1
    ADY
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    Matrices

    Help please

    Im trying to evaluate the following, but not sure if i'm going wrong,could someone please check this.

    Evaluating 2A + 3B

    Where

    A = \left(\begin{array}{cc}3&7\\4&-1\\-5&2\end{array}\right) B = \left(\begin{array}{cc}-5&-3\\10&6\end{array}\right)

    To evaluate i use the scalar multiplication?

    so:

    2A becomes = \left(\begin{array}{cc}6&14\\8&-2\\-10&4\end{array}\right)

    and

    3B becomes=  \left(\begin{array}{cc}-15&9\\30&18\end{array}\right)

    So my dillema is, i cant add these together can i because the incorrect rows to columns - or am i thinking this through to much?

    Thanks for your help

    Ady
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by ADY View Post
    Help please

    Im trying to evaluate the following, but not sure if i'm going wrong,could someone please check this.

    Evaluating 2A + 3B

    Where

    A = \left(\begin{array}{cc}3&7\\4&-1\\-5&2\end{array}\right) B = \left(\begin{array}{cc}-5&-3\\10&6\end{array}\right)

    To evaluate i use the scalar multiplication?

    so:

    2A becomes = \left(\begin{array}{cc}6&14\\8&-2\\-10&4\end{array}\right)

    and

    3B becomes=  \left(\begin{array}{cc}-15&9\\30&18\end{array}\right)

    So my dillema is, i cant add these together can i because the incorrect rows to columns - or am i thinking this through to much?

    Thanks for your help

    Ady
    Hi Ady,

    No, your thinking is just fine. You cannot add matrices with different dimensions.
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  3. #3
    ADY
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    Thanks Masters, so is that evaluated as far as possible?
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by ADY View Post
    Thanks Masters, so is that evaluated as far as possible?
    That would be correct.
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