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Math Help - area of rectangle

  1. #1
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    area of rectangle

    A rectangle has sides x and y.

    x=6-4y

    y= 15over2 -5x

    The area is 15over2 x - 5over4 xsquared.

    I don't know where the second part of the area comes from.
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  2. #2
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    Does the question make sense?
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  3. #3
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    Smile

    hi
    the area of your rectangle is x\times y.
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  4. #4
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    I want to produce the formula I gave. I think I've started the problem correctly.
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  5. #5
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    Quote Originally Posted by Stuck Man View Post
    A rectangle has sides x and y.

    x=6-4y

    y= 15over2 -5x

    The area is 15over2 x - 5over4 xsquared.

    I don't know where the second part of the area comes from.
    Hi Stuck Man,

    Your statement is not very clear to me. Use parentheses to delimit your terms. Use / for division instead of 'over'. Use ^2 for squared.

    Are you trying to solve this for x?

    (6-4y)\left(\frac{15}{2}-5x\right)=\frac{15}{2}x-\frac{5}{4}x^2
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  6. #6
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    I have to show that the area is given by that formula. I wrote the equations for x and y but I'm sure they are correct.
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  7. #7
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    Smile

    well..
    the area is Area= x\times y =\frac{15}{2}x-5x^2.
    since y= \frac{15}{2}-5x.
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  8. #8
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    I'll have to write the whole question. A window is y high and x long. There are 12 square sections layed out 3 by 4 so y is 1.33 times x. 30 metres of strip is used around all the pieces.

    I have to show that the area is given by the formula 15/2x-5/4x^2.
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  9. #9
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    I've seen what I did wrong. y = 15/2 -5x/4. That is multiplied by x to give the formula.

    How do you make writing appear in graphics here?
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  10. #10
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