1. ## area of rectangle

A rectangle has sides x and y.

x=6-4y

y= 15over2 -5x

The area is 15over2 x - 5over4 xsquared.

I don't know where the second part of the area comes from.

2. Does the question make sense?

3. hi
the area of your rectangle is $x\times y$.

4. I want to produce the formula I gave. I think I've started the problem correctly.

5. Originally Posted by Stuck Man
A rectangle has sides x and y.

x=6-4y

y= 15over2 -5x

The area is 15over2 x - 5over4 xsquared.

I don't know where the second part of the area comes from.
Hi Stuck Man,

Your statement is not very clear to me. Use parentheses to delimit your terms. Use / for division instead of 'over'. Use ^2 for squared.

Are you trying to solve this for x?

$(6-4y)\left(\frac{15}{2}-5x\right)=\frac{15}{2}x-\frac{5}{4}x^2$

6. I have to show that the area is given by that formula. I wrote the equations for x and y but I'm sure they are correct.

7. well..
the area is $Area=$ $x\times y$ $=\frac{15}{2}x-5x^2$.
since $y= \frac{15}{2}-5x$.

8. I'll have to write the whole question. A window is y high and x long. There are 12 square sections layed out 3 by 4 so y is 1.33 times x. 30 metres of strip is used around all the pieces.

I have to show that the area is given by the formula 15/2x-5/4x^2.

9. I've seen what I did wrong. y = 15/2 -5x/4. That is multiplied by x to give the formula.

How do you make writing appear in graphics here?