Thread: The problem in Functions again.

1. The problem in Functions again.

For the function f(x)=x^2-3x-2, find
a. f(0)
b. f(1)
c. f(-2)

a. =-2
b. =-4
c. =0

Can I get the right answer? If no, how can I do?

Cheers,

2. Originally Posted by turboman
For the function $f(x)=x^2-3x-2$, find
a. f(0)
b. f(1)
c. f(-2)

a. =-2
b. =-4
c. =0

Can I get the right answer? If no, how can I do?

Cheers,
You post it n the advanced topics but there is no difficulty on that.
c. $f(-2) = (-2)^2 - 3(-2) - 2 = 4 + 6 -2 = 8$