For the function f(x)=x^2-3x-2, find a. f(0) b. f(1) c. f(-2) My answer:- a. =-2 b. =-4 c. =0 Can I get the right answer? If no, how can I do? Cheers,
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Originally Posted by turboman For the function $\displaystyle f(x)=x^2-3x-2$, find a. f(0) b. f(1) c. f(-2) My answer:- a. =-2 b. =-4 c. =0 Can I get the right answer? If no, how can I do? Cheers, You post it n the advanced topics but there is no difficulty on that. c.$\displaystyle f(-2) = (-2)^2 - 3(-2) - 2 = 4 + 6 -2 = 8$
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