ab
Y-intercepts are found by setting the numerator equal to zero (since the fraction is equal to zero when the numerator is equal to zero) and solving.
Vertical asymptotes are found by setting the denominator equal to zero and solving.
The only way the $\displaystyle lx\, -\, 1$ and the $\displaystyle x\, -\, 1$ would not cancel is if $\displaystyle l\, \neq\, 1$.
See where these hints lead you....
hi
The only way $\displaystyle f $could have vertical asymptotes is when it's undefined.
$\displaystyle f $is undefined when $\displaystyle (kx-1)(lx+2)=0$.
the $\displaystyle y$-intercepts are the roots of your function,and $\displaystyle f$ will equal zero ONLY when $\displaystyle 4b(x-1)^2$ is equal to zero.