1. ab

2. Y-intercepts are found by setting the numerator equal to zero (since the fraction is equal to zero when the numerator is equal to zero) and solving.

Vertical asymptotes are found by setting the denominator equal to zero and solving.

The only way the $lx\, -\, 1$ and the $x\, -\, 1$ would not cancel is if $l\, \neq\, 1$.

See where these hints lead you....

3. hi
The only way $f$could have vertical asymptotes is when it's undefined.
$f$is undefined when $(kx-1)(lx+2)=0$.
the $y$-intercepts are the roots of your function,and $f$ will equal zero ONLY when $4b(x-1)^2$ is equal to zero.

4. Originally Posted by Raoh
the $y$-intercepts are the roots of your function,and $f$ will equal zero ONLY when $4b(x-1)^2$ is equal to zero.
the y intercepts are when x = 0
the x intercepts are the roots of the function

as x goes to (-)infinity the function tends to a certain limit(s), this limit is the/an asymptote

Edit: horizontal asymptotes