Changing subject forumla

**febbie22** · November 17th 2009, 09:57 AM

Hi i'm actaully at uni doing engineering i'm using this equation for trifilar suspension

T=2Pie*The Square Root of I*L Divided by M*r²*g

I need to change the Subject to Find I the mass moment of inertia

Any help would be great and sorry for not actualy using the right charaters.

**I4talent** · November 17th 2009, 10:18 AM

Originally Posted by febbie22

Hi i'm actaully at uni doing engineering i'm using this equation for trifilar suspension

T=2Pie*The Square Root of I*L Divided by M*r²*g

$T = 2\pi\sqrt\frac{IL}{Mr^2g}$ $\Rightarrow \frac{T}{2\pi} = \sqrt\frac{IL}{Mr^2g}$ $\Rightarrow \left(\frac{T}{2\pi}\right)^2 = \left(\sqrt\frac{IL}{Mr^2g}\right)^2$ $\Rightarrow \frac{T^2}{4\pi^2} = \frac{IL}{Mr^2g}$ $\Rightarrow \frac{\left(T^2\right)\left(Mr^2g\right)}{4\pi^2} = IL$ $\Rightarrow \boxed{\frac{\left(T^2\right)\left(Mr^2g\right)}{\ left(4\pi^2\right)\left(L\right)} = I}$

**febbie22** · November 17th 2009, 10:21 AM

Thanks alot

**curlylee93** · November 7th 2012, 01:11 PM

Hey, I know this was posted years ago, but ill post this for the sake of anyone else reading it now. I may be wrong, but shouldn't u end up with:

I = (T^2*Mr^2g)/(4pi^2*L) Should L not be on the bottom?

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