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Math Help - Quadratic Function

  1. #1
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    Quadratic Function

    Dear,
    i dun understand this question....

    If we translate y=5x(square) by p, in the positive direction of the x-axis, the graph passes thru the point (7,5).Find the values of p

    my friend taught me it should be y=5(x)^2, so its ..
    5 = 5(7-p)^2
    5 = and so on....until p=8 and 6

    i dun understand why the X became 7-p instead of just 7

    wud anybody explain to me? thank you
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  2. #2
    MHF Contributor

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    Quote Originally Posted by janeyandtaz View Post
    Dear,
    i dun understand this question....

    If we translate y=5x(square) by p, in the positive direction of the x-axis, the graph passes thru the point (7,5).Find the values of p

    my friend taught me it should be y=5(x)^2, so its ..
    5 = 5(7-p)^2
    5 = and so on....until p=8 and 6

    i dun understand why the X became 7-p instead of just 7

    wud anybody explain to me? thank you
    "Translating" a graph in the x direction just changes the x value: replace x with x-p or x+ p (it doesn't matter which).

    Here, translating the function y= 5x^2 by "p" gives y= 5(x-p)^2. Saying that its graph "passes through (7,5)" means that when x= 7, y= 5 so 5= 5(7- p)^2. We can divide both sides by 5 to get (7-p)^2= 1 so, taking square roots of both sides 7- p= \pm 1. If 7- p= 1, then -p= 1-7= -6 so p= 6. If 7- p= -1, then -p= -1-7= -8 so p= 8.
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  3. #3
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    thank you!
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