Dear,
i dun understand this question....

If we translate y=5x(square) by p, in the positive direction of the x-axis, the graph passes thru the point (7,5).Find the values of p

my friend taught me it should be y=5(x)^2, so its ..
5 = 5(7-p)^2
5 = and so on....until p=8 and 6

i dun understand why the X became 7-p instead of just 7

wud anybody explain to me? thank you

2. Originally Posted by janeyandtaz
Dear,
i dun understand this question....

If we translate y=5x(square) by p, in the positive direction of the x-axis, the graph passes thru the point (7,5).Find the values of p

my friend taught me it should be y=5(x)^2, so its ..
5 = 5(7-p)^2
5 = and so on....until p=8 and 6

i dun understand why the X became 7-p instead of just 7

wud anybody explain to me? thank you
"Translating" a graph in the x direction just changes the x value: replace x with x-p or x+ p (it doesn't matter which).

Here, translating the function $\displaystyle y= 5x^2$ by "p" gives $\displaystyle y= 5(x-p)^2$. Saying that its graph "passes through (7,5)" means that when x= 7, y= 5 so $\displaystyle 5= 5(7- p)^2$. We can divide both sides by 5 to get $\displaystyle (7-p)^2= 1$ so, taking square roots of both sides $\displaystyle 7- p= \pm 1$. If 7- p= 1, then -p= 1-7= -6 so p= 6. If 7- p= -1, then -p= -1-7= -8 so p= 8.

3. thank you!