Having trouble with this,
x^4 - 2x^3 + x^2 - 36 = 0
I found that (x+2)(x-3) are factors, but then how do I find the complex factors?
If you've found that (x + 2)(x - 3) is a factor of the original polynomial then you also know that:
(x^4 - 2x^3 + x^2 - 36)/[(x + 2)(x - 3)] = 0 for x not equal to -2 and 3. When you do the polynomial division you get:
x^2 - x + 6 = 0
I presume you can solve this from here?
-Dan