Having trouble with this,

x^4 - 2x^3 + x^2 - 36 = 0

I found that (x+2)(x-3) are factors, but then how do I find the complex factors?

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- Feb 11th 2007, 04:10 PMclassicstringsSolve over Complex Plane
Having trouble with this,

x^4 - 2x^3 + x^2 - 36 = 0

I found that (x+2)(x-3) are factors, but then how do I find the complex factors? - Feb 11th 2007, 04:14 PMtopsquark
If you've found that (x + 2)(x - 3) is a factor of the original polynomial then you also know that:

(x^4 - 2x^3 + x^2 - 36)/[(x + 2)(x - 3)] = 0 for x not equal to -2 and 3. When you do the polynomial division you get:

x^2 - x + 6 = 0

I presume you can solve this from here?

-Dan