3x - 5 > 0
I have one interval notation as (5/3, infinity).
but x is also less than 0 to negative infinity.
- 1st step (the denominator not equal 0 (zero))
since, the denominator is x so
Note: (!=) not equal
- 2nd step (the numerator)
so, we have
- 3rd step (create the number line)
create the number line with those two point we already have
first point is 0 and second point is
the line number devided the line into 3 intervals
( ,0); (0,5/3] and [5/3, )
- 4th step (check the point)
from the number line, you check the value of the point between the intervals and choose the positive value ( from the question).
......... hope it help...........