3x - 5> 0

x

I have one interval notation as (5/3, infinity).

but x is also less than 0 to negative infinity.

help please.

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- Nov 15th 2009, 06:44 PMcrashdummy[SOLVED] Solve inequality. Answer in interval notation.
__3x - 5__> 0

x

I have one interval notation as (5/3, infinity).

but x is also less than 0 to negative infinity.

help please. - Nov 15th 2009, 06:48 PMmathaddict
- Nov 16th 2009, 06:45 AMpencil09
$\displaystyle \frac{3x-5}{x}>0$

- 1st step (the denominator not equal 0 (zero))

since, the denominator is x so

$\displaystyle x (!=) 0$ Note: (!=) not equal

- 2nd step (the numerator)

$\displaystyle 3x-5=0$

so, we have $\displaystyle x=\frac{5}{3}$

- 3rd step (create the number line)

create the number line with those two point we already have

first point is 0 and second point is $\displaystyle \frac{5}{3}$

$\displaystyle -\infty$-----0----------5/3-------$\displaystyle \infty$

the line number devided the line into 3 intervals

($\displaystyle -\infty$,0); (0,5/3] and [5/3,$\displaystyle \infty$)

- 4th step (check the point)

from the number line, you check the value of the point between the intervals and choose the positive value ($\displaystyle >0$ from the question).

......... hope it help...........(Smirk)