3x - 5> 0

x

I have one interval notation as (5/3, infinity).

but x is also less than 0 to negative infinity.

help please.

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- November 15th 2009, 07:44 PMcrashdummy[SOLVED] Solve inequality. Answer in interval notation.
__3x - 5__> 0

x

I have one interval notation as (5/3, infinity).

but x is also less than 0 to negative infinity.

help please. - November 15th 2009, 07:48 PMmathaddict
- November 16th 2009, 07:45 AMpencil09

- 1st step (the denominator not equal 0 (zero))

since, the denominator is x so

Note: (!=) not equal

- 2nd step (the numerator)

so, we have

- 3rd step (create the number line)

create the number line with those two point we already have

first point is 0 and second point is

-----0----------5/3-------

the line number devided the line into 3 intervals

( ,0); (0,5/3] and [5/3, )

- 4th step (check the point)

from the number line, you check the value of the point between the intervals and choose the positive value ( from the question).

......... hope it help...........(Smirk)