Results 1 to 8 of 8

Math Help - Square roots help

  1. #1
    Junior Member
    Joined
    Apr 2008
    Posts
    51

    Square roots help

    Yeah, easy question, I know but I need some help with it.

    5\sqrt{24}+3\sqrt{10}
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by jscalalamoboy View Post
    Yeah, easy question, I know but I need some help with it.

    5\sqrt{24}+3\sqrt{10}
    First step, note that 5 \sqrt{24} + 3 \sqrt{10} = 5 \sqrt{4 \cdot 6} + 3 \sqrt{10}

    Now what can you do from here? And what exactly was your question...?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Apr 2008
    Posts
    51
    Quote Originally Posted by Jhevon View Post
    First step, note that 5 \sqrt{24} + 3 \sqrt{10} = 5 \sqrt{4 \cdot 6} + 3 \sqrt{10}

    Now what can you do from here? And what exactly was your question...?
    So.... 10 \sqrt {6} + 3 \sqrt {10}. That's where I'm stuck basically, can they be added?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by jscalalamoboy View Post
    So.... 10 \sqrt {6} + 3 \sqrt {10}. That's where I'm stuck basically, can they be added?
    no, they cannot be added. they are unlike terms.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member
    Joined
    Apr 2008
    Posts
    51
    Quote Originally Posted by Jhevon View Post
    no, they cannot be added. they are unlike terms.
    That's how I understood it. Is the question done? We are just supposed to simplify it.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by jscalalamoboy View Post
    That's how I understood it. Is the question done? We are just supposed to simplify it.
    If you are just supposed to simplify, then yes
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Junior Member
    Joined
    Apr 2008
    Posts
    51
    Crap, it's actually 10\sqrt{6} 3\cdot \sqrt{10} what does that change?
    Follow Math Help Forum on Facebook and Google+

  8. #8
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by jscalalamoboy View Post
    Crap, it's actually 10\sqrt{6} 3\cdot \sqrt{10} what does that change?
    Wow, that's one huge typo, dude!

    Of course that changes the answer!

    Notice that you have 10 \sqrt{630} and 630 = 9 \cdot 70
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. square roots
    Posted in the Algebra Forum
    Replies: 12
    Last Post: June 8th 2009, 10:21 PM
  2. square roots
    Posted in the Algebra Forum
    Replies: 4
    Last Post: February 9th 2009, 06:30 AM
  3. Square Roots
    Posted in the Pre-Calculus Forum
    Replies: 5
    Last Post: September 29th 2008, 05:58 PM
  4. square roots and i
    Posted in the Math Topics Forum
    Replies: 12
    Last Post: December 7th 2006, 02:25 PM
  5. Square Roots
    Posted in the Math Challenge Problems Forum
    Replies: 5
    Last Post: February 28th 2006, 07:35 AM

Search Tags


/mathhelpforum @mathhelpforum