1. ## Square roots help

Yeah, easy question, I know but I need some help with it.

$\displaystyle 5\sqrt{24}+3\sqrt{10}$

2. Originally Posted by jscalalamoboy
Yeah, easy question, I know but I need some help with it.

$\displaystyle 5\sqrt{24}+3\sqrt{10}$
First step, note that $\displaystyle 5 \sqrt{24} + 3 \sqrt{10} = 5 \sqrt{4 \cdot 6} + 3 \sqrt{10}$

Now what can you do from here? And what exactly was your question...?

3. Originally Posted by Jhevon
First step, note that $\displaystyle 5 \sqrt{24} + 3 \sqrt{10} = 5 \sqrt{4 \cdot 6} + 3 \sqrt{10}$

Now what can you do from here? And what exactly was your question...?
So.... $\displaystyle 10 \sqrt {6} + 3 \sqrt {10}$. That's where I'm stuck basically, can they be added?

4. Originally Posted by jscalalamoboy
So.... $\displaystyle 10 \sqrt {6} + 3 \sqrt {10}$. That's where I'm stuck basically, can they be added?
no, they cannot be added. they are unlike terms.

5. Originally Posted by Jhevon
no, they cannot be added. they are unlike terms.
That's how I understood it. Is the question done? We are just supposed to simplify it.

6. Originally Posted by jscalalamoboy
That's how I understood it. Is the question done? We are just supposed to simplify it.
If you are just supposed to simplify, then yes

7. Crap, it's actually $\displaystyle 10\sqrt{6} 3\cdot \sqrt{10}$ what does that change?

8. Originally Posted by jscalalamoboy
Crap, it's actually $\displaystyle 10\sqrt{6} 3\cdot \sqrt{10}$ what does that change?
Wow, that's one huge typo, dude!

Of course that changes the answer!

Notice that you have $\displaystyle 10 \sqrt{630}$ and $\displaystyle 630 = 9 \cdot 70$