Suppose f is a one-to-one function whose domain is given by the inequality -4 ≤ x ≤ 5
Suppose f is a one-to-one function whose domain is given by the inequality -4 ≤ x ≤ 5. The range of f is given by the inequality 0 ≤ f(x) ≤ 9. What is the domain of f-1?
Would the answer be -9 ≤ f-1(x) ≤ 0 or -4 ≤ f-1(x) ≤ 5
Suppose f is a one-to-one function whose domain is given by the inequality -4 ≤ x ≤ 5. The range of f is given by the inequality 0 ≤ f(x) ≤ 9. What is the domain of f-1?
Would the answer be -9 ≤ f-1(x) ≤ 0 or -4 ≤ f-1(x) ≤ 5
the domain and range of a function and it's inverse are "swapped".
Suppose f is a one-to-one function whose domain is given by the inequality -4 ≤ x ≤ 5. The range of f is given by the inequality 0 ≤ f(x) ≤ 9. What is the domain of f-1?
Would the answer be -9 ≤ f-1(x) ≤ 0 or -4 ≤ f-1(x) ≤ 5