Supposefis a one-to-one function whose domain is given by the inequality -4 ≤x ≤5.

The range offis given by the inequality 0 ≤f(x) ≤9.

What is the domain off-1?

Would the answer be -9 ≤f-1(x) ≤0 or -4 ≤f-1(x) ≤5 (Headbang)

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- Nov 15th 2009, 01:15 PMazninvasionSuppose f is a one-to-one function whose domain is given by the inequality -4 ≤ x ≤ 5
Suppose

*f*is a one-to-one function whose domain is given by the inequality -4 ≤*x ≤*5.

The range of*f*is given by the inequality 0 ≤*f(x) ≤*9.

What is the domain of*f*-1?

Would the answer be -9 ≤*f*-1(*x) ≤*0 or -4 ≤*f*-1(*x) ≤*5 (Headbang)

- Nov 15th 2009, 01:25 PMskeeter
- Nov 15th 2009, 01:44 PMazninvasion
so, does that mean the answer is -4 ≤

*x ≤*5???? - Nov 15th 2009, 01:59 PMe^(i*pi)
- Nov 15th 2009, 02:26 PMazninvasion
- Nov 15th 2009, 04:00 PMeliteplague
I think its your first answer,

- Nov 15th 2009, 04:03 PMazninvasion
0 ≤

*x ≤*9 maybe its this? haha this is like the hardest math problem on this forum >< - Nov 15th 2009, 04:19 PMskeeter
- Nov 15th 2009, 04:24 PMazninvasion
- Nov 15th 2009, 04:34 PMskeeter
- Nov 15th 2009, 06:04 PMKrahl