Originally Posted by Raoh Yes the same steps therefore I'm trying Range = (-2, inf)?
Last edited by mr fantastic; Nov 16th 2009 at 05:51 PM. Reason: Merged posts
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Originally Posted by Hellbent Range = (-2, inf)? If , then , provided the inverse exists. Look at what you defined your domain, or , to be in the initial problem.
Originally Posted by rowe If , then , provided the inverse exists. Look at what you defined your domain, or , to be in the initial problem. The domain is any number that's ≤ -2.
Originally Posted by Hellbent The domain is any number that's ≤ -2. Right, so the range of the inverse cannot be .
Originally Posted by rowe Right, so the range of the inverse cannot be . I know that the range is the set of output numbers, but I'm not understanding it here. (1, inf)?
Originally Posted by Hellbent I know that the range is the set of output numbers, but I'm not understanding it here. (1, inf)? In your above problem, you have given: f : x |→ (x + 1)² (x ∈ R, x ≤ -2)? So, we know the domain of to be . We know also know that if , then , and we can therefore conclude that the range of is .
THE DOMAIN OF IS THE RANGE OF AND VICE VERSA.
Thanks, rowe
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