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Math Help - Help with factorizing.

  1. #1
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    Help with factorizing.

    Hi, this is probably easy as hell for you guys but I'm just not the kind of guy who's supposed to be doing this ****, but i would really appreciate it if someone would help me with these because otherwise I'll get an F in the report card, this is higher level maths we're talking about, i'll change to lower level but need to do these first.

    factorize (if possible) as far as possible.

    a) 4a^2 - 2b^2/32


    b) 4x^2 + 12x^2 - 9


    c) 4x^3 - 3x^2 + 8x - 6
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  2. #2
    MHF Contributor alexmahone's Avatar
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    Quote Originally Posted by richardd View Post
    Hi, this is probably easy as hell for you guys but I'm just not the kind of guy who's supposed to be doing this ****, but i would really appreciate it if someone would help me with these because otherwise I'll get an F in the report card, this is higher level maths we're talking about, i'll change to lower level but need to do these first.

    factorize (if possible) as far as possible.

    a) 4a^2 - 2b^2/32


    b) 4x^2 + 12x^2 - 9


    c) 4x^3 - 3x^2 + 8x - 6
    a)\ 4a^2-\frac{2b^2}{32}

    = 4a^2-\frac{b^2}{16}

    = (2a)^2-(\frac{b}{4})^2

    = (2a+\frac{b}{4})(2a-\frac{b}{4})
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  3. #3
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by richardd View Post
    Hi, this is probably easy as hell for you guys but I'm just not the kind of guy who's supposed to be doing this ****, but i would really appreciate it if someone would help me with these because otherwise I'll get an F in the report card, this is higher level maths we're talking about, i'll change to lower level but need to do these first.

    factorize (if possible) as far as possible.

    a) 4a^2 - 2b^2/32


    b) 4x^2 + 12x^2 - 9


    c) 4x^3 - 3x^2 + 8x - 6
    4a^2 - \frac{2b^2}{32}

    4a^2 - \frac{b^2}{16} = \left(2a-\frac{b}{4}\right)\left(2a+\frac{b}{4} \right)

    from (x^2-y^2) = (x-y)(x+y)

    4x^2+12x^2-9

    16x^2-9 = (4x-3)(4x+3)

    4x^3-3x^2+8x-6

    4x^3+8x -3x^2 -6

    4x(x^2+2) -3(x^2+2) = (x^2+2)(4x-3)

    Hi, this is probably easy as hell for you guys
    hell is not easy for all
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  4. #4
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    Quote Originally Posted by richardd View Post
    a) 4a^2 - 2b^2/32

    b) 4x^2 + 12x^2 - 9

    c) 4x^3 - 3x^2 + 8x - 6
    a)
    4a^2 - \frac{2b^2}{32}
    = (2a)^2 - \frac{b^2}{16}
    = (2a)^2 - (\frac{b}{4})^2
    = (2a - \frac{b}{4})(2a + \frac{b}{4})

    b)
    4x^2 + 12x^2 - 9
    = 16x^2 - 3^2
    = (4x)^2 - 3^2
    = (4x - 3)(4x + 3)

    c)
    4x^3 - 3x^2 + 8x - 6
    = 4x^3 + 8x - 3x^2 - 6
    = (4x)(x^2 + 2) - (3)(x^2 + 2)
    = (4x  - 3)(x^2 + 2)

    ...a piece of cake.
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