Hi All,

I had the question to integrate $\displaystyle \int x \sqrt{2x+1} dx$ I've done the calculus bits, but I'm having trouble simplifying/factoring the algebra bits it to the correct answer.

My answer: $\displaystyle \frac{1}{10}{{(2x+1)}^{5/2}}-\frac{1}{6}{{(2x+1)}^{3/2}} + c$

The simplified answer: $\displaystyle \frac{1}{15}{{(2x+1)}^{3/2}}(3x-1) + c$

If anyone could show me the algebra steps to simplify it, or just give me a start of how to do it it would be much appreciated,

Thanks in advance.