# Thread: how to re-arrange this

1. ## how to re-arrange this 2. i also did this one is it correct? 3. Originally Posted by realistic  HI

$\displaystyle \log_{3}\sqrt{3^5}=\log_{3}(3^{\frac{5}{2}})$

$\displaystyle =\frac{5}{2}log_{3}3$

$\displaystyle =\frac{5}{2}$

4. Originally Posted by realistic i also did this one is it correct? yes its correct.

5. Originally Posted by mathaddict HI

$\displaystyle \log_{3}\sqrt{3^5}=\log_{3}(3^{\frac{5}{3}})$

$\displaystyle =\frac{5}{3}log_{3}3$

$\displaystyle =\frac{5}{3}$
in the back of the book they have $\displaystyle =\frac{5}{2}$

is that even possible for this question?

6. Originally Posted by realistic in the back of the book they have $\displaystyle =\frac{5}{2}$

is that even possible for this question?
oops , the book is correct . i misread the 3 as cube root . By the way , i edited mypost .

7. Originally Posted by mathaddict oops , the book is correct . i misread the 3 as cube root . By the way , i edited mypost .

ok thanks i c how it is done now #### Search Tags

rearrange 