# Thread: how to re-arrange this

1. ## how to re-arrange this

2. i also did this one is it correct?

3. Originally Posted by realistic
HI

$\log_{3}\sqrt{3^5}=\log_{3}(3^{\frac{5}{2}})$

$=\frac{5}{2}log_{3}3$

$
=\frac{5}{2}
$

4. Originally Posted by realistic
i also did this one is it correct?

yes its correct.

HI

$\log_{3}\sqrt{3^5}=\log_{3}(3^{\frac{5}{3}})$

$=\frac{5}{3}log_{3}3$

$
=\frac{5}{3}
$
in the back of the book they have $
=\frac{5}{2}
$

is that even possible for this question?

6. Originally Posted by realistic
in the back of the book they have $
=\frac{5}{2}
$

is that even possible for this question?
oops , the book is correct . i misread the 3 as cube root . By the way , i edited mypost .