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Math Help - how to re-arrange this

  1. #1
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    how to re-arrange this

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  2. #2
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    i also did this one is it correct?

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  3. #3
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    Quote Originally Posted by realistic View Post
    HI

    \log_{3}\sqrt{3^5}=\log_{3}(3^{\frac{5}{2}})

    =\frac{5}{2}log_{3}3

     <br />
=\frac{5}{2}<br />
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  4. #4
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    Quote Originally Posted by realistic View Post
    i also did this one is it correct?

    yes its correct.
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  5. #5
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    Quote Originally Posted by mathaddict View Post
    HI

    \log_{3}\sqrt{3^5}=\log_{3}(3^{\frac{5}{3}})

    =\frac{5}{3}log_{3}3

     <br />
=\frac{5}{3}<br />
    in the back of the book they have  <br />
=\frac{5}{2}<br />

    is that even possible for this question?
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  6. #6
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    Quote Originally Posted by realistic View Post
    in the back of the book they have  <br />
=\frac{5}{2}<br />

    is that even possible for this question?
    oops , the book is correct . i misread the 3 as cube root . By the way , i edited mypost .
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  7. #7
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    Quote Originally Posted by mathaddict View Post
    oops , the book is correct . i misread the 3 as cube root . By the way , i edited mypost .

    ok thanks i c how it is done now
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