x^log x = 100x How do I solve this? My book says the answers are 100 and .1 but how do I prove this. There is NOTHING in the book that answers this. Thanks
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Originally Posted by satx x^log x = 100x How do I solve this? My book says the answers are 100 and .1 but how do I prove this. There is NOTHING in the book that answers this. Thanks 1. 2. Your equation becomes: 3. This is a quadratic equation in . Solve for . You should come out with . 4. Calculate x.
Hello, satx! Solve for Note that Divide by We have: . Change-of-base Formula: . Multiply by Factor: . And we have: .
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