Could someone give me a hand with this one? Given that n[squared]+n=2k, how can (n+1)[squared]+(n+1) be written as a multiple of 2? Possible solutions: 2(k+1) 2(n+1) 2(n+k) 2(n+k+1)
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Originally Posted by gretchen Could someone give me a hand with this one? Given that n[squared]+n=2k, how can (n+1)[squared]+(n+1) be written as a multiple of 2? Possible solutions: 2(k+1) 2(n+1) 2(n+k) 2(n+k+1) Expand it and see from there. n^2 +n = 2k -----------(1) (n+1)^2 +(n+1) = (n^2 +2n +1) +(n+1) = n^2 +2n +1 +n +1 = (n^2 +n) +2n +2 = 2k +2n +2 = 2(k +n +1) ----------------answer.
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