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Math Help - [SOLVED] Which path should I take to solve this?

  1. #1
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    [SOLVED] Which path should I take to solve this?

    Q. -3 <= (3-5x)/3 < 3/8


    Should I do BEDMAS in reverse?
    eg. subtract 3 from all three sides to isolate the -5x
    or

    Should I multiply all three sides to remove the denominators?

    Thanks
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by crashdummy View Post
    Q. -3 <= (3-5x)/3 < 3/8


    Should I do BEDMAS in reverse?
    eg. subtract 3 from all three sides to isolate the -5x
    or

    Should I multiply all three sides to remove the denominators?

    Thanks
    Hi crashdummy,

    I believe I would multiply all three parts by 24 to clear the fractions.
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  3. #3
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    so does this look right?

    (see attachment)
    Attached Thumbnails Attached Thumbnails [SOLVED] Which path should I take to solve this?-asdf.png  
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  4. #4
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    hello
    -3\leq \frac{3-5x}{3}< \frac{3}{8}\Leftrightarrow -9\leq 3-5x< \frac{9}{8}\Leftrightarrow -12\leq -5x< \frac{-15}{8}\Leftrightarrow \frac{12}{5}\geq x> \frac{3}{8}
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  5. #5
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    Quote Originally Posted by Raoh View Post
    hello
    -3\leq \frac{3-5x}{3}< \frac{3}{8}\Leftrightarrow -9\leq 3-5x< \frac{9}{8}\Leftrightarrow -12\leq -5x< \frac{-15}{8}\Leftrightarrow \frac{12}{5}\geq x> \frac{3}{8}

    thanks,

    so my way is correct, just not in lowest terms as yours is.
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  6. #6
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    Quote Originally Posted by crashdummy View Post
    thanks,

    so my way is correct, just not in lowest terms as yours is.
    Exactly
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