# Thread: [SOLVED] Which path should I take to solve this?

1. ## [SOLVED] Which path should I take to solve this?

Q. -3 <= (3-5x)/3 < 3/8

Should I do BEDMAS in reverse?
eg. subtract 3 from all three sides to isolate the -5x
or

Should I multiply all three sides to remove the denominators?

Thanks

2. Originally Posted by crashdummy
Q. -3 <= (3-5x)/3 < 3/8

Should I do BEDMAS in reverse?
eg. subtract 3 from all three sides to isolate the -5x
or

Should I multiply all three sides to remove the denominators?

Thanks
Hi crashdummy,

I believe I would multiply all three parts by 24 to clear the fractions.

3. so does this look right?

(see attachment)

4. hello
$-3\leq \frac{3-5x}{3}< \frac{3}{8}\Leftrightarrow -9\leq 3-5x< \frac{9}{8}\Leftrightarrow -12\leq -5x< \frac{-15}{8}\Leftrightarrow \frac{12}{5}\geq x> \frac{3}{8}$

5. Originally Posted by Raoh
hello
$-3\leq \frac{3-5x}{3}< \frac{3}{8}\Leftrightarrow -9\leq 3-5x< \frac{9}{8}\Leftrightarrow -12\leq -5x< \frac{-15}{8}\Leftrightarrow \frac{12}{5}\geq x> \frac{3}{8}$

thanks,

so my way is correct, just not in lowest terms as yours is.

6. Originally Posted by crashdummy
thanks,

so my way is correct, just not in lowest terms as yours is.
Exactly