By changing the base of log..

Now solve this Equation....

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- November 9th 2009, 03:56 PM #1

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- Oct 2009
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- November 9th 2009, 04:50 PM #2

- November 9th 2009, 05:18 PM #3

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- May 2006
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- Lexington, MA (USA)
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- November 9th 2009, 05:36 PM #4

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- Oct 2009
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- November 9th 2009, 05:44 PM #5

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- Nov 2009
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