# Thread: Assorted Signed numers probs

1. ## Assorted Signed numers probs

Please solve and explain how these are solved.

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The steps should be fairly transparent:

$\displaystyle \frac{x}{6} - (-10) = 3$

$\displaystyle \frac{x}{6} + 10 = 3$

$\displaystyle \frac{x}{6} + 10 - 10 = 3 - 10$

$\displaystyle \frac{x}{6} = -7$

$\displaystyle 6 \cdot \frac{x}{6} = 6 \cdot (-7)$

$\displaystyle x = -42$

-Dan

Please solve and explain how these are solved.

$\displaystyle \frac{x}{2} = 6$

$\displaystyle 2 \cdot \frac{x}{2} = 2 \cdot 6$

$\displaystyle x = 12$

-Dan

Please solve and explain how these are solved.

Based on what I did in the first two, show me what you think you ought to do. Don't worry if it's wrong or incomplete, just post what you can get.

-Dan

5. 41?

6. Originally Posted by topsquark
Based on what I did in the first two, show me what you think you ought to do. Don't worry if it's wrong or incomplete, just post what you can get.

-Dan
41?
Well, I was kinda hoping you'd show me how you did it so I could point out where you were right and, perhaps, where you went wrong.

$\displaystyle 30 + y = -10$

We need to get y by itself, so I'm going to take away 30 from the RHS. Thus I also have to take away 30 from the LHS:
$\displaystyle 30 + y - 30 = -10 - 30$

$\displaystyle y = -40$

-Dan

7. I just figured that thirty minus forty is ten. The long process is still a little confusing.