# Thread: Assorted Signed numers probs

1. ## Assorted Signed numers probs

Please solve and explain how these are solved.

2. [quote=radioflyer01;38585]Please solve and explain how these are solved.

[\quote]
The steps should be fairly transparent:

$\frac{x}{6} - (-10) = 3$

$\frac{x}{6} + 10 = 3$

$\frac{x}{6} + 10 - 10 = 3 - 10$

$\frac{x}{6} = -7$

$6 \cdot \frac{x}{6} = 6 \cdot (-7)$

$x = -42$

-Dan

3. Originally Posted by radioflyer01
Please solve and explain how these are solved.

$\frac{x}{2} = 6$

$2 \cdot \frac{x}{2} = 2 \cdot 6$

$x = 12$

-Dan

4. Originally Posted by radioflyer01
Please solve and explain how these are solved.

Based on what I did in the first two, show me what you think you ought to do. Don't worry if it's wrong or incomplete, just post what you can get.

-Dan

5. 41?

6. Originally Posted by topsquark
Based on what I did in the first two, show me what you think you ought to do. Don't worry if it's wrong or incomplete, just post what you can get.

-Dan
Originally Posted by radioflyer01
41?
Well, I was kinda hoping you'd show me how you did it so I could point out where you were right and, perhaps, where you went wrong.

$30 + y = -10$

We need to get y by itself, so I'm going to take away 30 from the RHS. Thus I also have to take away 30 from the LHS:
$30 + y - 30 = -10 - 30$

$y = -40$

-Dan

7. I just figured that thirty minus forty is ten. The long process is still a little confusing.

8. Originally Posted by radioflyer01
I just figured that thirty minus forty is ten. The long process is still a little confusing.
Just keep at it. You'll get there. The whole process can be long or short, depending on the person, but we've all been there and gotten through it. Practice is the key!

-Dan