$\log_[x]{81} - \log_[2x]{36}=2$
Hello,
have a look here: http://www.mathhelpforum.com/math-he...-tutorial.html
EB
Hello,
I assume that you know
and
With the LCD is:
After a few simple transformations you should get:
(From this point the Latex doesn't work properly. I'll post the rest as plain text)
I'm using now the logarithms in decimal form. Substitute: y=ln(x) and you'll get:
Now re-substitute using and you'll get: .
Probably there is a more elegant and easier way to solve this equation - but I couldn't find it.
EB
PS.: Obviously the Latex is back to duty!
If you have a new question, please post it in a new thread.
(Your "\" on the last LaTeX bracket is backward.)
Take the first equation:
Then insert this into the second equation:
(*)
<-- Square both sides.
<-- Squaring again.
I can't find a way to factor this thing, so I'm going to suggest a numerical solution. I get that x = 4 and x = 5.8 or so. (The other two solutions don't work.) Thus y = 1 and y = 0.591681084 or so, respectively.
-Dan