# Math Help - Please help me start this

1. ## Please help me start this

$\sqrt[3]{2x^2+8x+8}=\sqrt[3]{x^2-4}$

2. Originally Posted by sandersc69
$\sqrt[3]{2x^2+8x+8}=\sqrt[3]{x^2-4}$
Start by cubing both sides. Then you have a quadratic.