# Please help me start this

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• Nov 8th 2009, 05:29 PM
sandersc69
Please help me start this
$\sqrt[3]{2x^2+8x+8}=\sqrt[3]{x^2-4}$
• Nov 8th 2009, 05:40 PM
VonNemo19
Quote:

Originally Posted by sandersc69
$\sqrt[3]{2x^2+8x+8}=\sqrt[3]{x^2-4}$

Start by cubing both sides. Then you have a quadratic.