• November 8th 2009, 05:29 PM
sandersc69
$\sqrt[3]{2x^2+8x+8}=\sqrt[3]{x^2-4}$
• November 8th 2009, 05:40 PM
VonNemo19
Quote:

Originally Posted by sandersc69
$\sqrt[3]{2x^2+8x+8}=\sqrt[3]{x^2-4}$

Start by cubing both sides. Then you have a quadratic.