# Rearrange formula?

• Nov 8th 2009, 03:58 PM
nexer
Rearrange formula?
Hi i am struggling with a problem, i have to rearrange a formula making B the subject.

x=b-c/a

If anyone could help me through this i would be very appreciative.
• Nov 8th 2009, 04:05 PM
VonNemo19
Quote:

Originally Posted by nexer
Hi i am struggling with a problem, i have to rearrange a formula making B the subject.

x=b-c/a

If anyone could help me through this i would be very appreciative.

Does subject mean output?
• Nov 8th 2009, 04:08 PM
nexer
believe so, i need to rearrange the formula so i can work other stuff out from the rearranged formula.
• Nov 8th 2009, 04:13 PM
Bacterius
Just add \$\displaystyle c/a\$ on both sides (unless you miswrote your equation, because it seems too easy).
• Nov 8th 2009, 04:16 PM
nexer
umm. . . its (b-c)/a if that makes a difference?
• Nov 8th 2009, 04:20 PM
VonNemo19
Quote:

Originally Posted by nexer
umm. . . its (b-c)/a if that makes a difference?

In that case, mult. both sides by a, then add c to both sides.
• Nov 8th 2009, 04:24 PM
nexer
So i'm getting b=xa+c? looks too simple to be true. but thanks for all help.
• Nov 8th 2009, 04:31 PM
VonNemo19
Quote:

Originally Posted by nexer
So i'm getting b=xa+c? looks too simple to be true. but thanks for all help.

Well, as I said before, I'm not entirely certain what "subject" means as it relates to math. That's a new one for me.

I think we're right though.
• Nov 8th 2009, 05:57 PM
Bacterius
Quote:

Originally Posted by VonNemo19
Well, as I said before, I'm not entirely certain what "subject" means as it relates to math. That's a new one for me.

I think we're right though.

I think what he means by subject is the variable one is willing to evaluate (so it is on its own on a side of the equation). It's the same term in physics too. So, I think we're right too.