I have this:
X = ABC + BCD
(BCD has a not line over it)
The answer should be:
X = ABCD
(X and A have a not line over them)
Can someone show me the steps to get to the answer?
Hello,
$\displaystyle \bar X=(\overline{ABC})(BCD)=(\bar A+\bar B+\bar C)(BCD)$ $\displaystyle =\bar A BCD+\bar B BCD+\bar C BCD=\bar A BCD+(\bar B B)CD+(\bar C C)BD$
Recall that for any P, $\displaystyle \bar P P=0$, that + and * are associative, etc...