I have to find a little riddle , but i don't find a résulat.

can you help me please ?!

http://i33.tinypic.com/jtt5ad.jpg

:)

thx you!

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- Nov 6th 2009, 01:19 PMjadee[SOLVED] calcul riddle
I have to find a little riddle , but i don't find a résulat.

can you help me please ?!

http://i33.tinypic.com/jtt5ad.jpg

:)

thx you! - Nov 6th 2009, 01:23 PMWilmer
C'est quoi la question?

- Nov 6th 2009, 01:25 PMjadee
il faut résoudre A

- Nov 6th 2009, 01:28 PMWilmer
Solve for A?!

That makes no sense. - Nov 6th 2009, 01:38 PMBacteriusReply
Tu ne peux pas trouver un résultat sans avoir une question ... quelle est-elle donc ?

You can't find a solution without having a question ... so what is it ? - Nov 6th 2009, 01:48 PMmr fantastic
- Nov 6th 2009, 01:54 PMBacteriusReply
I'll give a clue (don't have time either) :

Which makes me think this expression might simplify to a constant. - Nov 6th 2009, 01:55 PMDefunkt
- Nov 6th 2009, 01:56 PMDebsta
Yes you've got to simplify the expression and you will find all the n's evenyuallu cancel out. I got 216 as the value for A.

Start by writing 8 as 2^3 and 4 as 2^2.

Then use your index laws and factorising.

A few hints: (2^3)^(n+1) = 2^(3n+3) = 2^(3n) x 2^3.

Give it a try....I'll check in again later if you need more help. Good luck. - Nov 6th 2009, 01:59 PMDebsta