For any with , prove that

Printable View

- Nov 6th 2009, 01:12 PMPQRInequality
For any with , prove that

- Nov 6th 2009, 01:38 PMbigwave
with abc = 1

then

therefore

- Nov 6th 2009, 01:59 PMKrizalid
you don't have a proof, that's a particular case you just took.

- Nov 10th 2009, 06:05 AMPQR
- Jan 4th 2010, 04:04 PMKrizalid
and now by Cauchy - Schwarz we have finally