Solve for x....
2^(2x+1) = 3^(2x-5)
Thanks addict, the answer on my tutorial sheet must be wrong...
I completed it by doing
(2x + 1)log2=(2x - 5)log3
2xlog2+log2=2xlog3-5log3
2xlog3-2xlog2=log2+5log3
2x(log3-log2)=log2+5log3
2x=(log2+5log3)/(log3-log2)......
I get the same answer doing it this way, was pulling my hair out for ages.
Thanks again