Solve for x....
2^(2x+1) = 3^(2x-5)
HI
Apply log to both sides ,
$\displaystyle
\log 2^{2x+1}=\log 3^{2x-5}
$
$\displaystyle (2x+1)\log 2=(2x-5)\log 3$
$\displaystyle \frac{2x+1}{2x-5}=\frac{\log 3}{\log 2}$
$\displaystyle \frac{2x+1}{2x-5}=1.585$
$\displaystyle 2x+1=1.585(2x-5)$
Can you take it from here ?
Thanks addict, the answer on my tutorial sheet must be wrong...
I completed it by doing
(2x + 1)log2=(2x - 5)log3
2xlog2+log2=2xlog3-5log3
2xlog3-2xlog2=log2+5log3
2x(log3-log2)=log2+5log3
2x=(log2+5log3)/(log3-log2)......
I get the same answer doing it this way, was pulling my hair out for ages.
Thanks again