make x subject(in terms of a and b) 4a/6 +3(x-4)=ax+b 4a +18(x-4)=6ax+6b 4a+18x-72=6ax+6b 18x=6ax+6b+72-4a 6ax+6b+72-4a/x=17x??
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Originally Posted by wolfhound make x subject(in terms of a and b) 4a/6 +3(x-4)=ax+b 4a +18(x-4)=6ax+6b 4a+18x-72=6ax+6b 18x=6ax+6b+72-4a *** 6ax+6b+72-4a/x=17x?? HI *** continuing from here , $\displaystyle 18x-6ax=6b+72-4a$ $\displaystyle x(18-6a)=6b+72-4a$ $\displaystyle x=\frac{6b+72-4a}{18-6a}$ $\displaystyle =\frac{3b+36-2a}{9-3a} $
excellent,thanks for your quick reply
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