I have a log problem $\displaystyle \log_{3}x-2\log_{x}3=1$ the question is asking to find the values of x.

I started the problem by changing the base

$\displaystyle \log_{3}x-\frac {2}{\log_{3}x}-1=0$

$\displaystyle (\log_{3}x)^2-2-\log_{3}x=0$

$\displaystyle y^2-y-2=0$

Am I on the right track? Can someone help me with this problem?