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Math Help - Modulus

  1. #1
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    Modulus

    Sketch y= abs (x-3) + abs(x+3)
    and find the solution set of the equation abs (x-3) + abs (x+3) =6

    Thanks!!
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  2. #2
    Super Member bigwave's Avatar
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    solve for -x then +x

    since x can be postive or negative
    solve for both

    x is positive

    x - 3 + x + 3 = 6
    2x = 6
    x = 3

    x is negative

    -x - 3 - x + 3 = 6
    -2x = 6
    x = -3

    so your solution set is [-3,3]

    to test this let x = a number within this set like 2

    |2 - 3| + |2 + 3| = 6

    if you graph this you will see a horz line between (-3,6) to (3,6)
    Last edited by mr fantastic; November 5th 2009 at 03:45 AM. Reason: Changed font size to normal so that reply could be read without using a microscope.
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  3. #3
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    Quote Originally Posted by Oasis1993 View Post
    Sketch y= abs (x-3) + abs(x+3)
    and find the solution set of the equation abs (x-3) + abs (x+3) =6

    Thanks!!
    I suggest graphing y = abs(x - 3) and y = abs(x + 3) and then using the addition of ordinates technique.
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