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Math Help - algebra, solve x

  1. #1
    desmon
    Guest

    algebra, solve x

    Hi,

    heres the question i was working on, which originally asked to add some algebraic fractions. That part was fine but I'm asked to find x and am stuck here.

    3x^2 + 5x - 2
    ------------- = 0
    3x^2 + 2x



    Any help is greatly appreciated.

    Thanks
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  2. #2
    Junior Member AlvinCY's Avatar
    Joined
    Feb 2007
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    I live in Sydney, Australia.
    Posts
    69
    Quote Originally Posted by desmon View Post
    Find x.

    \frac{3x^2 + 5x - 2}{3x^2 + 2x} = 0

    Any help is greatly appreciated.

    Thanks
    \frac{3x^2 + 5x - 2}{3x^2 + 2x} = 0 inplies that 3x^2 + 5x - 2 = 0 and that  3x^2 + 2x \not = 0

    Solving 3x^2 + 5x - 2 = 0

    3x^2 + 5x - 2 = 0
    3x^2 + 6x - x - 2 = 0
    3x(x + 2) - (x + 2) = 0
    (3x - 1)(x + 2) = 0

    So x = \frac{1}{3} or  x = -2

    Checking the condition that  3x^2 + 2x \not = 0

     3x^2 + 2x \not = 0
     x(3x + 2) \not = 0
     x \not = 0 or x \not = -\frac{2}{3}
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