1)-12x^2-4x+1
2)2(x-3)^2+18
Thanks to anyone who can help me!
So we have $\displaystyle y = -12x^2-4x+1
$
The $\displaystyle x$-intercept happens when $\displaystyle y = 0$, so let
$\displaystyle -12x^2-4x+1 = 0
$ and then solve for $\displaystyle x$.
The y-intercept happens when $\displaystyle x = 0$, so we let
$\displaystyle -12(0)^2-4(0)+1 = y$, and then we have $\displaystyle y$. Do the same to second.