The fifth root of 1/32 w^6 z^7?
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Originally Posted by Schatzle06 The fifth root of 1/32 w^6 z^7? $\displaystyle 1/32=1/2^5$ Thus, $\displaystyle (1/2^5)w^5 z^5 wz^2$ Then the fifth root assuming it exists is, $\displaystyle (1/2)wz\sqrt[5]{wz^2}$
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