Could someone please help me write this radical quotient in lowest terms? My textbook didn't give me an example for one like this. I'm confused.
$\displaystyle \frac{12-\sqrt{40}}{4}$
All it wants you to do is simplify the radical, which gives you:
$\displaystyle \frac{12-2\sqrt{10}}{4}$
Then you can simplify the fraction by writing it like: $\displaystyle \frac{2(6)-2\sqrt{10}}{2(2)}$
Then cancel the twos: $\displaystyle \frac{\not{2}(6)-\!\!\not{2}\sqrt{10}}{\not{2}(2)}$
Therefore: $\displaystyle \frac{12-\sqrt{40}}{4}=\frac{6-\sqrt{10}}{2}$
Do you need help on simplifying the radical?