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Thread: "Writing a Radical Quotient in Lowest Terms"

  1. #1
    Newbie firefly_senshi6's Avatar
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    "Writing a Radical Quotient in Lowest Terms"

    Could someone please help me write this radical quotient in lowest terms? My textbook didn't give me an example for one like this. I'm confused.

    $\displaystyle \frac{12-\sqrt{40}}{4}$
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  2. #2
    MHF Contributor Quick's Avatar
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    Quote Originally Posted by firefly_senshi6 View Post
    Could someone please help me write this radical quotient in lowest terms? My textbook didn't give me an example for one like this. I'm confused.

    $\displaystyle \frac{12-\sqrt{40}}{4}$
    All it wants you to do is simplify the radical, which gives you:

    $\displaystyle \frac{12-2\sqrt{10}}{4}$

    Then you can simplify the fraction by writing it like: $\displaystyle \frac{2(6)-2\sqrt{10}}{2(2)}$

    Then cancel the twos: $\displaystyle \frac{\not{2}(6)-\!\!\not{2}\sqrt{10}}{\not{2}(2)}$

    Therefore: $\displaystyle \frac{12-\sqrt{40}}{4}=\frac{6-\sqrt{10}}{2}$

    Do you need help on simplifying the radical?
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  3. #3
    Newbie firefly_senshi6's Avatar
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    Ahhhh, I see what I was doing wrong, now. For some reason, instead of doing this:

    $\displaystyle \frac{12-2\sqrt{10}}{4}$

    I did this:

    $\displaystyle \frac{12(2)-\sqrt{10}}{4}$


    Thank you so much for your help! Now I know where I've been messing up.
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