HI How is this solved with quadratic formula: 3n^2-21n+38=20 ps. I put 3 instead of a, 21 instead of b, and 38 instead of c, but I can't get the result I want. I know n=6, but how do i get this..?
Follow Math Help Forum on Facebook and Google+
Originally Posted by alternative HI How is this solved with quadratic formula: 3n^2-21n+38=20 ps. I put 3 instead of a, 21 instead of b, and 38 instead of c, but I can't get the result I want. I know n=6, but how do i get this..? $\displaystyle b = -21$ $\displaystyle c = 18$
could I ask why c=18, thanks a lot
Originally Posted by alternative could I ask why c=18, thanks a lot because the quadratic equation works if $\displaystyle ax^2 + bx + c = 0$
ouppppssss :$ Thank you, so so so much..
View Tag Cloud