(y/7)^2 + ((x-1)/3)^2 = 1 How do I go about doing this?
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Originally Posted by clambottomjewels (y/7)^2 + ((x-1)/3)^2 = 1 How do I go about doing this? This is the equation of an ellipse: So what exactly do you want to do with it? EDIT: OK, finally I read the headline Can you take it from here?
Originally Posted by clambottomjewels (y/7)^2 + ((x-1)/3)^2 = 1 How do I go about doing this? Take from both sidesTake the square root of both sides (and don't forget the Multiply both sides by 7 You should get an answer of . This is equivalent to
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