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Problems say The sums and products of pairs of integers are given. find each paor of integers.
sum = -12, product = 36
sum = -12, product = 35
sum = -12, product = 32
sum = -12, product = 11
sum = -12, product = 0
please help... I cant do this :confused:
Well the long way would be to solve algebraicaly two equations with two unknowns like this:
x+y=-12
x*y=36
solve the first eq for x:
x=-12-y
now sub it into eq 2
(-12-y)(y)=36
-12y-y^2=36
-y^2-12y-36=0
y^2+12y+36=0
(y+6)(y+6)=0
y=-6
now sub into either eq and solve for x
The short way to do it is just by looking at it.
1. -6,-6
2. -7,-5
4. -8,-4
5. -11,-1
6. -12,0