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Math Help - Solving Rational equations.

  1. #1
    Junior Member
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    Solving Rational equations.

    i understand how to do this, but wow i am not able to get the correct answer for this question.

    (x-1/x-2) - (x+1/1-x) = -1
    when i get rid of the denominators by multiplying both sides of the equation by (x-2)(1-x) i end up getting:
    2x-x^2-1-x^2+x+2 = 3x- x^2-2
    simplified:
    x^2-3 = 0

    When i use the quadratic formula to solve it get x=1.7

    the answers are 0.2, 1.8

    help?
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  2. #2
    MHF Contributor
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    Quote Originally Posted by t-dot View Post
    2x-x^2-1-x^2+x+2 = 3x- x^2-2
    Right side should be x^2 - 3x + 2 ; you forgot to multiply by -1

    That'll lead you to 3x^2 - 6x + 1 = 0
    Solve that using quadratic equation.
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  3. #3
    Member
    Joined
    May 2009
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    New Delhi
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    Quote Originally Posted by t-dot View Post
    i understand how to do this, but wow i am not able to get the correct answer for this question.

    (x-1/x-2) - (x+1/1-x) = -1
    when i get rid of the denominators by multiplying both sides of the equation by (x-2)(1-x) i end up getting:
    2x-x^2-1-x^2+x+2 = 3x- x^2-2
    simplified:
    x^2-3 = 0

    When i use the quadratic formula to solve it get x=1.7

    the answers are 0.2, 1.8

    help?
    it should be
    2x-x^2-1-x^2+x+2 = -(3x- x^2-2)
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  4. #4
    Junior Member
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    Oct 2007
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    i knew i was missing something easy....
    thanks guys.
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  5. #5
    Newbie
    Joined
    Nov 2009
    Posts
    5

    rational inequalities

    Ok, trying to work on rational inequalities: all examples show probs with common denominators, what if you don't have that? Yes, you divide right? still can't get it tho! here's one of my many problems:
    4/(x+5) >=(how the hell do you do the math signs?!) I mean greater or equal to btw, 2/(x-2). I need a drink
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