A draughtsman wants to draw a square with area 2m^2. How could he do this without having to measure out the irrational sides? Clue: start with a square with double the area.
I have been at this problem for half an hour now -no joy!? Help!
A draughtsman wants to draw a square with area 2m^2. How could he do this without having to measure out the irrational sides? Clue: start with a square with double the area.
I have been at this problem for half an hour now -no joy!? Help!
draw two perpendicular line segments of length = 2 m that intersect at their respective midpoints ... connect the four ends to form a square.
I'll leave it to you to convince yourself that the area = 2 square meters
draw two perpendicular line segments of length = 2 m that intersect at their respective midpoints ... connect the four ends to form a square.
I'll leave it to you to convince yourself that the area = 2 square meters
OK. I got how that explanation works. Thanks!
But, the question specifically wants us to use a square double the size, i.e. use a square of area 4m squared to solve the problem of drawing one of 2m squared without having to measure it out.
Last edited by GAdams; October 31st 2009 at 11:07 AM.
Reason: got it eventually