f(x)=x^pi

Thanks

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- Oct 30th 2009, 10:01 PMgoc335Why doesn't this function work when x<0 ?
f(x)=x^pi

Thanks - Oct 30th 2009, 10:21 PMFailure
For arbitrary $\displaystyle b\in\mathbb{R}$, $\displaystyle x^b$ is defined to be nothing other than the value of $\displaystyle \mathrm{e}^{b\cdot\ln(x)}$. If you

*can*define $\displaystyle \ln(x)$ for negative x, fine (I would be surprised if you could, but then: who am I?), if you*can't*: there you go!