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Math Help - Why doesn't this function work when x<0 ?

  1. #1
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    Why doesn't this function work when x<0 ?

    f(x)=x^pi

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  2. #2
    Super Member Failure's Avatar
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    Quote Originally Posted by goc335 View Post
    f(x)=x^pi

    Thanks
    For arbitrary b\in\mathbb{R}, x^b is defined to be nothing other than the value of \mathrm{e}^{b\cdot\ln(x)}. If you can define \ln(x) for negative x, fine (I would be surprised if you could, but then: who am I?), if you can't: there you go!
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