Originally Posted by

**TKHunny** Very bad! Logs can help you take apart MULTIPLICATION not addition. However, this does not seem to be what you ahve done, either. You seem to thing the "log" is some sort of factor. This is not the case. You cannot distribute a FUNCTION through to the elements of its argument.

"log" doesn't mean anything in this context. It MUST have an argument. "log(x)", now that means something.

In this problem, you are supposed to recognize and exploit this one thing, $\displaystyle 3^{2} = 9$. You will also use the base transformation rules.

$\displaystyle log_{3}(x) = log_{9}(2x-1)$

Transform to a common base.

$\displaystyle \frac{log(x)}{log(3)} = \frac{log(2x-1)}{log(9)}$

Now what?