Originally Posted by

**Monocerotis** __Question__

The base of a triangle is 2cm more than the height. The area of the triangle is $\displaystyle 5cm^2$. Find the base to the nearest tenth of a centimeter.

__Attempt @ Solution__

Area of Triangle = $\displaystyle 1/2((b)(h))$

Let x represent h (height), and let x represent b (base)

h = x

b = x + 2

$\displaystyle 2x+x^2 / 2=5 $

$\displaystyle 2x+x^2=10 $

$\displaystyle x^2+2x-10=0$

Standard Form: a = 1, b= 2, c= 10

Sub in values into quadratic equation and solve for x which would give you the height, then add 2 to that value which would give you the base.

Is this correct ?