Results 1 to 3 of 3

Math Help - Reducing fractions??

  1. #1
    Newbie
    Joined
    Oct 2009
    From
    SEATTLE SHUT UP
    Posts
    3

    Reducing fractions??

    Not sure what to title this, but im having trouble with this problem in particular.

    (17a^2b^3)/(18 yx) / (34 a ^2 )/(9xy)

    I tried multiplying by the reciprocal:

    (17 a^2 b^3) / (18 yx) * (9xy)/(34 a^2)

    came up with

    153b^3 /612 = b^3/4 [is this right??]
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    29
    Quote Originally Posted by iamcoffee View Post
    Not sure what to title this, but im having trouble with this problem in particular.

    (17a^2b^3)/(18 yx) / (34 a ^2 )/(9xy)

    I tried multiplying by the reciprocal:

    (17 a^2 b^3) / (18 yx) * (9xy)/(34 a^2)

    [is this right??]
     \frac{17 a^2 b^3}{18 yx} \times \frac{9xy}{34 a^2}= \frac{b^3}{4}
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor

    Joined
    Apr 2005
    Posts
    16,445
    Thanks
    1863
    Notice that you can write \frac{17 a^2 b^3}{18 yx} \times \frac{9xy}{34 a^2} as \frac{17}{34}\frac{9}{18}\frac{a^2}{a^2}\frac{x}{x  }\frac{y}{y}b^3
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Reducing non-linear laws to linear fractions
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: November 17th 2011, 03:16 PM
  2. Reducing the set
    Posted in the Advanced Algebra Forum
    Replies: 6
    Last Post: October 7th 2009, 12:02 PM
  3. Reducing Fractions Questions
    Posted in the Algebra Forum
    Replies: 3
    Last Post: October 31st 2008, 11:19 AM
  4. Reducing Algebra Fractions by -1
    Posted in the Algebra Forum
    Replies: 8
    Last Post: August 23rd 2008, 04:13 PM
  5. Reducing Fractions
    Posted in the Algebra Forum
    Replies: 1
    Last Post: August 3rd 2006, 01:07 AM

Search Tags


/mathhelpforum @mathhelpforum